Quiz: what will happen when the following code is run[*]?<div><div><br></div><div>=================</div><div><div>    class Trait {</div><div>        fun void announce() { &lt;&lt;&lt; &quot;I am generic.&quot; &gt;&gt;&gt;; }</div>
<div>        fun void invoke() { announce(); }</div><div>    }</div><div>    class Legacy extends Trait {</div><div>        fun void announce() { &lt;&lt;&lt; &quot;I am legacy.&quot; &gt;&gt;&gt;; }</div><div>    }</div>
<div>    class Lunacy extends Trait {</div><div>        public void announce() { &lt;&lt;&lt; &quot;I am lunacy.&quot; &gt;&gt;&gt;; }</div><div>    }</div><div>    (new Legacy).invoke();</div><div>    (new Lunacy).invoke();</div>
<div><div>=================</div><div><br></div><div>If you predict that it prints:</div><div><div><br></div><div>    &quot;I am legacy.&quot; : (string)</div><div>    &quot;I am lunacy.&quot; : (string)</div><div><br></div>
<div>then here&#39;s a hint: there&#39;s a typo in the definition of Lunacy&#39;s announce() method where it says &quot;public void announce()...&quot; instead of &quot;fun void announce()...&quot;.  </div><div><br></div>
<div>If you predict that it gets a compiler error when it encounters the typo, well, you&#39;d be wrong there as well.  What happens instead is that it compiles without any error messages, and the result is:</div><div><br>
</div><div><div>    &quot;I am legacy.&quot; : (string)</div><div>    &quot;I am generic.&quot; : (string)</div><div><br></div><div>It took me a LONG time to find this one (and an even longer time to boil it down to a succinct example).  Will the powers that be please take this as a request to beef up the parser?</div>
<div><br></div><div>Thanks.</div><div><br></div><div>- Rob</div><div><br></div><div>[*] in particular, chuck v 1.2.1.3 mac os x : intel.  I&#39;m guessing that this is platform independent, though...</div><div><br></div></div>
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