Currently in ChucK, a parent shred will terminate any child shreds when the parent terminates. For example:
--- // start fun void foo() { <<< "foo!!!" >>>; }
// spork foo spork ~ foo();
// end of program ---
In this case, "foo" will NOT print because the parent shred has exited before the child has a chance to run. As Kassen mentioned, advancing time in the parent shred will allow children to execute. If no time advance is desired, me.yield() should work.
--- // start fun void foo() { <<< "foo!!!" >>>; }
// spork foo spork ~ foo();
// yield to let foo run, no time advance me.yield();
// end of program ---
Hope this helps.
Yep. Unless foo() is doing something non-trivial. For example, dur T1; dur T2; fun void foo() { T1 => now; <<< "foo!!!" >>>; } // spork foo spork ~ foo(); T2 => now; In this case "foo" will print only if T2 > T1. ___________________ w31rd0