Re: [chuck-users] making a duration into a string?

Sure, can do, but this is only for debugging -- I'd welcome a means to get the same effect as <<< "duration is", d >>>; which obviously works, but not as a string. Same comments apply for stringifying a time value. - Rob On Sat, Jan 9, 2010 at 13:08, Andrew Turley wrote:

Are you looking for a way to generate something that would ultimately generate a string that contains "1::second"? Because if that's the case, you probably can't do it. Durations ultimately get stored as floats that represent the number of samples in the duration. And they don't, as far as I know, retain any information about the units that were used when they were created. So 6::second and 0.1::minute will both be stored as the number of samples that are contained in a 6 second interval.

Now, what you can do is convert the duration to a float by doing this:

1::second => dur d; d / (1::samp) => float dSamp;

And then you could convert that float to a string. Now what you probably want is a duration in terms of time rather than samples, so you could also get the number of samples per second and divide dSamp by that number, and then store your duration as a string representation of a floating point number represented in terms of seconds (or maybe you want milliseconds).

andy

On Sat, Jan 9, 2010 at 12:50 PM, Robert Poor wrote:

...

How can I cast a duration into a string (e.g. for passing as a string argument)?  Consider:

// ============= fun void log(string message) {  // do something to log the message }

1::second => dur d; log("the duration is " + d);  // fails with "cannot perform '+' on object references" log("the duration is " + d.toString()); // fails with "type 'dur' does not have members" // =============

Same question for time objects.

TIA.

- Rob _______________________________________________ chuck-users mailing list chuck-users@lists.cs.princeton.edu https://lists.cs.princeton.edu/mailman/listinfo/chuck-users

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