I'm not the most qualified to answer your questions, but I'll take a shot (besides my brain needs a break from the research I've been doing). If anyone wants to correct me, please jump in.

Passing default values: As Far As I Know, ChucK does not support default values in formal arguments.

Of "now" and timestamps: You are well on your way to discovering a fundamental truth about ChucK: "now" is the current time in the virtual machine. In effect, it advances only when sound is being synthesized, not when your code is being run. From the point of view of your code, now advances only when you execute some form of:

where x is a duration, a time, or an event. So the following code will advance "now" by 1000 units (where one unit turns out to be one sample):

On the other hand, the following code will not advance now at all:

for (0 => int i; i<REALLY_HUGE_NUMBER; i++) {

Math.sqrt(2.0) => float y;

... since the code doesn't have any calls to "x => now".

Moral of the story: ChucKs 'now' facility is for precise timing of synthesized audio. It's not the same as a Unix time function.

Does that answer your question?

On 22 Jun 2009, at 16:15, Bozelos Dimitris wrote:

Hello everyone!

1) can default values be passed to a function? I've tried all of

   fun void test( int i = 0)
   fun void test( 0 => int i)
   fun void test( int i => 0)

but nothing works and in the manual nothing is stated. Anybody knows? I would be surprised if you cannot pass default values to a function. Why if so?

2) by printing <<< now >>>; I get the timestamp from the virtual machine, but if I do

<<<now>>>;

/// do some stuff

<<<now>>>;

the two outputs are exactly the same even if the stuff in between last for some seconds. Why? How can I know the duration of something?

Cheers,

Dimitris

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