Re: [chuck-users] shreds, namespace, functions, classes, etc

Hello, I think it's not so much a question of 'what a shred is', as a more general issue of the scope of variables that are declared within a function (ie, they are not accessible outside the scope of said function). I'm about to leave my house, and not feeling quite clear enough to explain more completely, but I hope that's enough to point you in the right direction. Cheers, Peter On Nov 15, 2007 4:46 PM, Kassen wrote:

Dear list,

Shreds are objects (of type Shred) and functions aren't objects. This is all good and well but it gets harder when we spork a function and the function becomes a Shred and hence a Object. Consider this;

------------------------ fun void tester() { "boom" => string beep; while(1) { <<<beep>>>; second => now; } }

spork ~ tester() @=> Shred foo; 5::second => now;

"clik" => foo.beep; //this doesn't work

day=> now; ----------------------------------------

It's not so clear to me *why* the offending line doesn't work. Maybe I'm misunderstanding something or making a syntax error but I think that what we are seeing here is a loss of namespace that would be useful and I don't understand why this happens.

I also tried stuff along these lines;

---------------------- class Bar extends Shred { //stuff including variables and a constructor } ------------------------------

If I do that I can instantiate a "Bar" but all it does is run it's constructor; I can't manage to spork a Bar or assign a sporked shred to a Bar. I can also make a array of Bar's but all that gets me is the constructor running;

--------------------------- class Bar extends Shred { static int number; <<>>; }

//print a series of numbers, no shreds in sight Bar array[5]; ----------------------------------

So, now I'm quite happy I said so many times that there are no "stupid n00b questions" because now it's my turn to ask exactly what a "Shred" is because I'm starting to feel like I have no idea. :¬)

Could somebody please explain to me exactly what's going on here?

Yours, Kas.

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