Found out why I was getting "empty" arrays. It seems there is some inconsistency with the way array.size() behaves. This is, - when an empty array is created, size() and cap() differ. - when cells of an empty array are filled individually, size() and cap () differ - when an array is created and cells' values are assigned with @=> operator, size() = cap(). So size() cannot be trusted to return the actual size of the array. I was using size() to loop thru my array which returned 0, and thus thought I had an empty array. Is this a bug? or is it supposed to work like this.? I remember there was a discussion in the past about this and believe we were told to use cap() instead of size(). I used size() just because of being used to other programing languages, so I think that if size is not to be used, it should be removed. Eduard code explaining it: int a[3]; <<<"empty array.", "Checking if .cap == .size">>>; <<<"a.size()=", a.size(), "a.cap()=", a.cap() >>>; for( 0 => int i; i < a.cap(); i++ ) i => a[i]; <<<"filled array.", "Checking if .cap == .size">>>; <<<"a.size()=", a.size(), "a.cap()=", a.cap() >>>; <<< "array created by @=>">>>; [1, 2, 3] @=> int b[]; <<<"b.size()=", b.size(), "b.cap()=", b.cap() >>>; On Oct 14, 2007, at 12:04 AM, Cesare Marilungo wrote:
eduard aylon wrote:
This seems something I should have done in the past, but I can't figure out how to return an array from a function. Couldn't find documentation nor examples.
case 1: compiling error. This seems the more natural way to me.
fun int return_array( int a[] ) { return a; }
case 2: works, but the returned array is empty
fun int[] return_array( int a[] ) { return a; }
Hi, case 2 works here:
[ 1,2,3 ] @=> int anarray[];
fun int[] return_array( int a[] ) { return a; }
<<< return_array( anarray )[0] >>>; //prints: 1: (int)
thanks,
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