me.numArgs() broken?
Is me.numArgs() broken? This code taken from the concurency/shreds page of language specification: // print out all arguments for( int i; i < me.numArgs(); i++ ) <<< me.arg( i ) >>>; returns this error: "class 'Shred' has no member 'numArgs'"
it's just me.args(). i think numArgs() was from a pre-release version. dt On Aug 6, 2008, at 12:03 PM, N. Cameron Britt wrote:
Is me.numArgs() broken?
This code taken from the concurency/shreds page of language specification: // print out all arguments for( int i; i < me.numArgs(); i++ ) <<< me.arg( i ) >>>;
returns this error: "class 'Shred' has no member 'numArgs'"
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Daniel Trueman
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N. Cameron Britt