[chuck-users] benchmarking chuck

[eduard aylon]

On May 3, 2006, at 12:58 AM, Perry R Cook wrote:

> OK, here's the deal with that original code.
>
>       s1 @=>  a[counter] => dac;
>
> The first Chuck does assignment (replaces that
> member of the array with s1.  The 2nd Chuck
> connects it to the dac.  The @ part of the
> operator signifies assignment.  So it's all legal,
> but maybe confusing.


I understand  @ as "reference to". Same as & in C. Is this the  
correct way of understanding it?