[chuck-users] benchmarking chuck
eduard.aylon at gmail.com
Tue May 2 19:10:08 EDT 2006
On May 3, 2006, at 12:58 AM, Perry R Cook wrote:
> OK, here's the deal with that original code.
> s1 @=> a[counter] => dac;
> The first Chuck does assignment (replaces that
> member of the array with s1. The 2nd Chuck
> connects it to the dac. The @ part of the
> operator signifies assignment. So it's all legal,
> but maybe confusing.
I understand @ as "reference to". Same as & in C. Is this the
correct way of understanding it?
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