[chuck-users] shreds, namespace, functions, classes, etc

[Peter Todd]

Hello,

I think it's not so much a question of 'what a shred is', as a more general
issue of the scope of variables that are declared within a function (ie,
they are not accessible outside the scope of said function).  I'm about to
leave my house, and not feeling quite clear enough to explain more
completely, but I hope that's enough to point you in the right direction.

Cheers,
Peter

On Nov 15, 2007 4:46 PM, Kassen <signal.automatique at gmail.com > wrote:

> Dear list,
>
> Shreds are objects (of type Shred) and functions aren't objects. This is
> all good and well but it gets harder when we spork a function and the
> function becomes a Shred and hence a Object. Consider this;
>
> ------------------------
> fun void tester()
>     {
>     "boom" => string beep;
>     while(1)
>         {
>         <<<beep>>>;
>         second => now;
>         }
>     }
>
>
> spork ~ tester() @=> Shred foo;
> 5::second => now;
>
> "clik" => foo.beep; //this doesn't work
>
> day=> now;
> ----------------------------------------
>
> It's not so clear to me *why* the offending line doesn't work. Maybe I'm
> misunderstanding something or making a syntax error but I think that what we
> are seeing here is a loss of namespace that would be useful and I don't
> understand why this happens.
>
> I also tried stuff along these lines;
>
> ----------------------
> class Bar extends Shred
>     {
>     //stuff including variables and a constructor
>     }
> ------------------------------
>
> If I do that I can instantiate a "Bar" but all it does is run it's
> constructor; I can't manage to spork a Bar or assign a sporked shred to a
> Bar. I can also make a array of Bar's but all that gets me is the
> constructor running;
>
> ---------------------------
> class Bar extends Shred
>     {
>     static int number;
>     <<<number++>>>;
>     }
>
> //print a series of numbers, no shreds in sight
>  Bar array[5];
> ----------------------------------
>
> So, now I'm quite happy I said so many times that there are no "stupid
> n00b questions" because now it's my turn to ask exactly what a "Shred" is
> because I'm starting to feel like I have no idea. :¬)
>
> Could somebody please explain to me exactly what's going on here?
>
>
> Yours,
> Kas.
>
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>
>
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