[chuck-users] osc listener shred woes

[Kassen]

2008/4/28 Stefan Blixt <stefan.blixt at gmail.com>:

> I don't know about the segv signal, but it seems to me that there is only
> one Bang instance that is shared by all iterations/shreds. This means that
> if two events arrive at this loop:
>
>        while( oe.nextMsg() ) {
>            oe.getInt() => b.value;
>            osctype => b.message;
>            b.broadcast();
>        }
>
> the second's values will overwrite those of the first (value and message
> from the first event will be lost).


I think that's right and I think the way around this would be

       while( oe.nextMsg() ) {
           oe.getInt() => b.value;
           osctype => b.message;
           b.broadcast();
           //yield to receiving shreds,
           //then continue processing the message cue
           me.yield();
       }

This is the exact same principle I talked about earlier in this topic; if
you don't yield you don't give the waiting shreds a chance to run. Advancing
time here would probably not be a good idea.

Yours,
Kas.
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