[chuck-users] LiSa SndBuf rate bug?

[dan trueman]

'tis an example. change the line:

2. => lisa.rate;

to whatever you want to get a different rate. just make sure you change:

lisa.duration() * 0.5 => now;

to an appropriate value as well, to make sure it plays long enough....

dt

On Nov 14, 2008, at 8:10 PM, mike clemow wrote:

> Hey folks,
>
> In the below example (which you will all find in the LiSa-SndBuf.ck
> file in examples in your installation), after populating the buffer in
> the LiSa object with the values of the samples from SndBuf, the rate
> of the LiSa object is set equal to 2. in order to play back normally.
> Why is it not 1?  Why this should be the case makes little sense to me
> and I respectfully submit this as a bug, unless someone can provide a
> reasonable explanation.
>
> Thoughts?
>
> -Mike
>
>
> -----
>
> //ugens
> SndBuf buf;
> LiSa lisa => dac;
>
> //change this path to your own sample
> "/Users/dan/Files/Chuck/LiSa_examples/TomVega.wav" => buf.read;
>
> //set lisa buffer size to sample size
> buf.samples() * 1::samp => lisa.duration;
>
> //transfer values from SndBuf to LiSa
> for ( 0 => int i; i < buf.samples(); i++ ) {
>
> 	//args are sample value and sample index (dur must be integral in  
> samples)
> 	lisa.valueAt(buf.valueAt(i), i::samp);
> 	
> }
>
> //party on...
> 1  => lisa.play;
> 2. => lisa.rate;
>
> //look at some of the data
> //returns value at given time, with linear interpolation
> <<< Std.rand2f( 0., lisa.duration() / 1::samp ) :: samp  =>  
> lisa.valueAt >>>;
>
> //hang on until it's done...
> lisa.duration() * 0.5 => now;
>
> -- 
> http://michaelclemow.com
> http://semiotech.org
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