[chuck-users] object / class hacking
Stefan Blixt
stefan.blixt at gmail.com
Wed Sep 30 09:31:08 EDT 2009
More importantly, how do you get a nice hash key?
You can iterator over contents on a simple array, store the keys there like:
string hashKeys[];
That's what you usually use to iterate over when doing hashmaps anyway (if
you want to iterate over contents what do you need the hash for?)
Here's a pseudocode attempt at a hashset (I keep forgetting the subtleties
of @ and the autogrowing array syntax is missing from the annoying manual):
class HashElement {
fun int hashCode();
}
class HashSet {
HashElement elements[][];
fun int contains(HashElement @ element) {
elements[element.hashCode()] @=> HashElement @ hashedList[];
for (0 => int i; i < hashedList.cap(); i++) {
if (hashedList[i] == element) {
return 1;
}
}
return 0;
}
fun void insert(HashElement @ element) {
elements[element.hashCode()] @=> HashElement @ hashedList[];
if (hashedList == null) {
HashElement[1] @=> hashedList;
hashedList @=> elements[element.hashCode()];
}
element +=> hashedList[]; // keep forgetting the syntax for
autogrowing the array
}
}
The elements you want to put in the hash set need to extend HashElement.
/Stefan
2009/9/30 Robert Poor <rdpoor at gmail.com>
> Hans:
> Of course I'd love to use a hashmap. But how do you get one in Chuck?
> AFIK, the existing chuckain "hash array" lacks a means to iterate over its
> contents.
>
> - Rob
>
> On 30 Sep 2009, at 02:03, Hans Aberg wrote:
>
> On 30 Sep 2009, at 02:13, Robert Poor wrote:
>
> I guess the question should be: what's the fastest way to maintain a *set*
> of objects (i.e. a collection in which an object may only appear once) with
> the usual operations for insertion, deletion and iteration?
>
>
> For lookup tables, if you do not need to compare the keys, a hash map is
> fastest - time complexity O(1), otherwise a balanced tree (like C++
> std::map) - complexity O(log n). There might be some C++ hash map classes at
> <http://www.boost.org/>. But if n is small and use not too intense, just
> about any container will do.
>
> Hans
>
>
>
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>
>
--
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