[chuck-users] making a duration into a string?

Robert Poor rdpoor at gmail.com
Sat Jan 9 16:16:32 EST 2010


Sure, can do, but this is only for debugging -- I'd welcome a means to
get the same effect as
  <<< "duration is", d >>>;
which obviously works, but not as a string.  Same comments apply for
stringifying a time value.

- Rob

On Sat, Jan 9, 2010 at 13:08, Andrew Turley <aturley at acm.org> wrote:
> Are you looking for a way to generate something that would ultimately
> generate a string that contains "1::second"? Because if that's the
> case, you probably can't do it. Durations ultimately get stored as
> floats that represent the number of samples in the duration. And they
> don't, as far as I know, retain any information about the units that
> were used when they were created. So 6::second and 0.1::minute will
> both be stored as the number of samples that are contained in a 6
> second interval.
>
> Now, what you can do is convert the duration to a float by doing this:
>
> 1::second => dur d;
> d / (1::samp) => float dSamp;
>
> And then you could convert that float to a string. Now what you
> probably want is a duration in terms of time rather than samples, so
> you could also get the number of samples per second and divide dSamp
> by that number, and then store your duration as a string
> representation of a floating point number represented in terms of
> seconds (or maybe you want milliseconds).
>
> andy
>
> On Sat, Jan 9, 2010 at 12:50 PM, Robert Poor <rdpoor at gmail.com> wrote:
>> How can I cast a duration into a string (e.g. for passing as a string
>> argument)?  Consider:
>>
>> // =============
>> fun void log(string message) {
>>  // do something to log the message
>> }
>>
>> 1::second => dur d;
>> log("the duration is " + d);  // fails with "cannot perform '+' on
>> object references"
>> log("the duration is " + d.toString()); // fails with "type 'dur' does
>> not have members"
>> // =============
>>
>> Same question for time objects.
>>
>> TIA.
>>
>> - Rob
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