[chuck-users] LiSa question

[Jeff Albert]

> That code worked for me.
>  
> My first thought to solving that problem would be to use 2 different instances of LiSa, but what you did works too.  

--Jeff Albert
Assistant Professor (Extraordinary) of Music Industry Studies
Loyola University New Orleans
Office: Communications/Music Complex 428P
Office Phone: (504) 865-2606
Google Voice: (504) 315-5167
jvalbert at loyno.edu (mailto:jvalbert at loyno.edu)
http://www.loyno.edu/~jvalbert


On Sunday, December 9, 2012 at 11:30 AM, Aurélien Bondis wrote:

> Hi,
> I'm trying to figure out how to have multiple samples of different sizes
> looping together.
> I think I kind of have it but would like to be sure :)
> Are the voices here for that?
> Record does not have a voice option, so I understand that I have to
> explicitly tell my sample what part of it is supposed to be 'voice 1' or
> 'voice 2'.
> Also in my code, I seem to have my voice2 starting from something like
> 1second before its end and then loop, did I miss something ?
>  
> Here is my code:
> ---------------------------------------------------------
> //a simple signal path
> adc => LiSa saveme => dac;
>  
> //gotta tell LiSa how much memory to allocate
> 60::second => saveme.duration;
>  
> saveme.recRamp(200::ms);
> <<< "recording 1" >>>;
> 1::second => now;
> 1 => saveme.record;
> 3::second => now;
> 0 => saveme.record;
> // Set voice 1 start and stop to use in the loop
> saveme.loopStart(1, 0::second);
> saveme.loopEnd(1, 3::second);
> <<< "recording 2" >>>;
> 1::second => now;
> 1 => saveme.record;
> 10::second => now;
> 0 => saveme.record;
> // Set voice 2 start and stop to use in the loop
> saveme.loopStart(2, 3::second);
> saveme.loopEnd(2, 13::second);
> // set voice 1 to loop
> saveme.loop(1,1);
> // set voice 2 to loop
> saveme.loop(2,1);
> <<< "playing">>>;
> // play loops
> saveme.play(1,1);
> saveme.play(2,1);
> while (true) {
> 1::second => now;
> }
> ------------------------------------------------------------
>  
> Thanks for your help.
> Aurélien.
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>  


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