[chuck-users] chuck output to console on stdout
Jordan Orelli
jordanorelli at gmail.com
Wed Dec 12 21:48:15 EST 2012
two ways to do it that I know of:
put it on its own line with this:
<<< T >>>
or just divide by one sample, because that's the base unit of duration:
T / 1::samp
will yield the number of samples in the duration. That's how it's normally printed with <<< T >>> anyway. Getting the human time like having it say 1.5s would mean you'd have to factor in the current sampling rate, not sure if that's accessible from ChucK code itself.
-jordan
On Wednesday, December 12, 2012 at 9:44 PM, Aurélien Bondis wrote:
> Hi,
>
> I don't know for sure if this applies to your version but in the doc it
> says chout and stdout have been disabled
>
> http://chuck.cs.princeton.edu/doc/language/overview.html
> "For the time being, stdout and chout have been temporarily disabled for
> the present release. In their place we have provided a debug print"
>
> Aurélien
>
> On Thu, 13 Dec 2012, stephane.poirier at oifii.org (mailto:stephane.poirier at oifii.org) wrote:
>
> > Hi All,
> >
> > Here below are 3 lines of code in chuck. How could I modify it to output the value of T in the chout?
> >
> > // this synchronizes to period
> > 0.75::second => dur T;
> > T - (now % T) => now;
> > // output to console on stdout
> > chout <= 1 <= " foo " <= 5.5 <= IO.newline();
> >
> > Regards,
> >
> > Stephane
>
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> >
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>
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