[chuck-users] No simple vibrato example

[Moisés Gabriel Cachay Tello]

You can always try to modulate the Oscilator:

SinOsc vibrato => SinOsc sine => dac;
// This will tell sine to take the vibrato input as a modulator of
// it's frequency.
2 => sine.sync;

5 => vibrato.freq;
10 => vibrato.gain;

5::second => now;


2013/12/4 Manuel Bärenz <manuel at enigmage.de>

> Hi guys,
>
> I'm giving a presentation on ChucK tomorrow and I wanted to show off
> some of the basic features in a live coding session. I found that
> creating a vibrato (modulating the frequency) is far too hard. The
> example I'm looking at is
> http://chuck.cs.princeton.edu/doc/examples/basic/whirl.ck. In an
> infinite loop, you have this code:
>
>     30 + ( Math.sin(t) + 1.0 ) * 10000.0 => s.sfreq;
>     t + .004 => t;
>
> Here, t is a float and s is a SinOsc. Now, what I would have expected is
> the following, more intuitive setup outside the loop:
>
> 30 + SinOsc freq_mod => s.freq;
> 1 => freq_mod.freq;
>
> I know that the first line with the "30 + SinOsc" is probably nonsense
> in itself, but I could work around that (by using a step UGen for
> example). My actual problem is that you can't chuck a SinOsc into s.freq.
> Consider this line:
>
> SinOsc freq_mod => s.freq;
>
> I get an error like this:
> arguments type(s) do not match:
> ... for function 'SinOsc.freq(...)' ...
> ...(please check the argument types)
>
> Is this something that the language is simply not capable of or am I
> doing something wrong?
>
> Best, Manuel
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>



-- 
-Moisés
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